The three boxes 1,2,3 has values resp. AB,BC,AC Get 2A(B+C) +AC-2C(A-B)in Box 1 using only addition in 3 steps.

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The three boxes 1,2,3 has values resp. AB,BC,AC Get 2A(B+C) +AC-2C(A-B)in Box 1 using only addition in 3 steps.

GIVEN: 2A(B+C)+AC-2C(A-B)
THEREFORE 2AB+2AC+AC-2AC+2BC
2AB+AC+2BC
2(AB+BC)+AC
LET b1=AB b2=BC b3=AC
STEP1: b1 = b1+b2
so b1 = AB+BC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AC
STEP 2: b3 = b1+b3
so b3 = AB+BC+AC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AB+BC+AC
STEP3:
NOW: b1 = b1+b3
so b1 = AB+BC+AB+BC+AC
=2(AB+BC)+ AC
AB BC AC
STEP1 AB+BC BC AC
STEP2 AC BC AB+BC+AC
STEP3 AB+BC+AB+BC+AC BC AB+BC+AC
i.e 2(AB+BC)+AC BC AB+BC+AC

Same as above but step 2 should be add box 1 to box 1. A
little pedantic but but I would deduct marks for not meeting
the requirements.

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