Given a triangle ABC, how would you use only a compass and straight edge to find a point P such that triangles ABP, ACP and BCP have equal perimeters? (Assume that ABC is constructed so that a solution does exist.)

Given a triangle ABC, how would you use only a compass and straight edge to find a point P such that triangles ABP, ACP and BCP have equal perimeters? (Assume that ABC is constructed so that a solution does exist.)

Given a triangle ABC, how would you use only a compass and straight edge to find a point P such that triangles ABP, ACP and BCP have equal perimeters? (Assume that ABC is constructed so that a solution does exist.)

The answer probably lies in finding the in-centre of the
traingle. Bisect all the angles of the triangles and the
point where these angle bisectors meet gives u the point P

take a equilateral 3angle…. place compass pt @ each vertices.. draw an arc… mark d pt wr all arcs meet.. thats d pt P ….. thus it gives 3angle of equal perimeter

The answer probably lies in finding the in-centre of the

traingle. Bisect all the angles of the triangles and the

point where these angle bisectors meet gives u the point P