A pipe can fill a tank in 30 min B can fill in 28 min then if 3/4 th of tank can be filled by B pipe and after wards both are opened then how much time is required by both the pipes to fill the tank completely.
Anonymous Answered question December 25, 2022
24.6 min (not sure)
24 min
1 minute B can fill 1/28 part of tank
1 minute A can fill 1/30 part of tank
So 3/4 part of tank can be filled in 28(3/4) time by B = 21 minutes
In 1minute both the pipe can fill (1/28 + 1/30) part of tank ,so 1/4 the part can be filled in (28*30/58 )*1/4 =3.6
So total time =21+3.6=24
Aprox. 4.6 min if both opened simultaneously
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105/29 mins